(x^2)+5*x=1400

Solution for (x^2)+5*x=1400 equation:

(x^2)+5x=1400

We move all terms to the left:

(x^2)+5x-(1400)=0

a = 1; b = 5; c = -1400;
Δ = b2-4ac
Δ = 52-4·1·(-1400)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-75}{2*1}=\frac{-80}{2}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+75}{2*1}=\frac{70}{2}
=35
$